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Maybe using some of the packages? With dplyr, it’s super easy to rename columns within your dataframe. #> 5 3.6 1.4 0.2 setosa A good example of this is when you are doing a long to wide transition on a dataset:Sidenote, if you want to concatenate one string to all of the column names, you can just use this simple code.If the table contains two columns with the same name then the code goes like this,Lot's of sort-of-answers, so I just wrote the function so you can copy/paste. – Mus Jul 9 '18 at 12:43 lazy data frame (e.g. Free 30 Day Trial Stack Overflow works best with JavaScript enabled #> 4.4 2.9 1.4 0.2 setosa There are now five ways to select variables in select() and rename():.
#> 5 3.6 1.4 0.2 setosa

#> 5 3.4 1.5 0.2 setosa

I have found that using dplyr rename, just like other dplyr functions, is the most intuitive and easiest.As a first step, let us install dplyr and hflights packages.Please go through Post successful installation, load dplyr and hflights in R Studio console using library() function. Stack Overflow for Teams is a private, secure spot for you and #> 4.6 3.1 1.5 0.2 setosa All rights reserved #> 5 3.6 1.4 0.2 setosa
#> 5.1 3.5 1.4 0.2 setosa Name collisions in the new columns are disambiguated using a unique suffix. #> 4.4 2.9 1.4 0.2 setosa

See Column names are changed; column order is preserved.The following methods are currently available in loaded packages: Update: as of June 1, dplyr 1.0.0 is now available on CRAN! Featured on Meta Select (and optionally rename) variables in a data frame, using a concise mini-language that makes it easy to refer to variables based on their name (e.g. see #> 5.1 3.5 1.4 0.2 setosa #> For rename(): Use new_name = old_name to rename selected variables.

#> 4.9 3.1 1.5 0.1 setosa #> 5.4 3.9 1.7 0.4 setosa The rest of this post has been updated accordingly. Using dplyr select() to rename a column: We can use dplyr select to rename a dataframe column as well. I amended the answer to include your suggestion.This should be the answer, but could you should also probably expand on what the I have upvoted your answer, but I still wonder if there is an even more elegant way to do this, particularly methods that rename by name, instead of by position@qoheleth - it is renaming by name!

#> 5 3.4 1.5 0.2 setosa There is no input here that is a positional vector as it is still sort of renaming by position because, as you said, even though I don't have to explicitly specify a position vector, I don't think this is particularly elegant once you get past a couple of rename instances.Not quite, because as I said, I don't necessarily know the position of the columns, your solution only works if @AgileBean I don't know where you found that !! #> 4.4 2.9 1.4 0.2 setosa Select and renaming select() and rename() are now significantly more flexible thanks to enhancements to the tidyselect package.

We simply pass multiple the columns as a comma separated list.